113 lines
No EOL
3.2 KiB
JavaScript
113 lines
No EOL
3.2 KiB
JavaScript
import boolbase from "boolbase";
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/**
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* Returns a function that checks if an elements index matches the given rule
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* highly optimized to return the fastest solution.
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*
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* @param parsed A tuple [a, b], as returned by `parse`.
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* @returns A highly optimized function that returns whether an index matches the nth-check.
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* @example
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*
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* ```js
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* const check = nthCheck.compile([2, 3]);
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*
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* check(0); // `false`
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* check(1); // `false`
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* check(2); // `true`
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* check(3); // `false`
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* check(4); // `true`
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* check(5); // `false`
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* check(6); // `true`
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* ```
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*/
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export function compile(parsed) {
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const a = parsed[0];
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// Subtract 1 from `b`, to convert from one- to zero-indexed.
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const b = parsed[1] - 1;
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/*
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* When `b <= 0`, `a * n` won't be lead to any matches for `a < 0`.
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* Besides, the specification states that no elements are
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* matched when `a` and `b` are 0.
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*
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* `b < 0` here as we subtracted 1 from `b` above.
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*/
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if (b < 0 && a <= 0)
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return boolbase.falseFunc;
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// When `a` is in the range -1..1, it matches any element (so only `b` is checked).
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if (a === -1)
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return (index) => index <= b;
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if (a === 0)
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return (index) => index === b;
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// When `b <= 0` and `a === 1`, they match any element.
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if (a === 1)
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return b < 0 ? boolbase.trueFunc : (index) => index >= b;
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/*
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* Otherwise, modulo can be used to check if there is a match.
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*
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* Modulo doesn't care about the sign, so let's use `a`s absolute value.
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*/
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const absA = Math.abs(a);
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// Get `b mod a`, + a if this is negative.
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const bMod = ((b % absA) + absA) % absA;
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return a > 1
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? (index) => index >= b && index % absA === bMod
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: (index) => index <= b && index % absA === bMod;
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}
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/**
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* Returns a function that produces a monotonously increasing sequence of indices.
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*
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* If the sequence has an end, the returned function will return `null` after
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* the last index in the sequence.
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*
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* @param parsed A tuple [a, b], as returned by `parse`.
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* @returns A function that produces a sequence of indices.
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* @example <caption>Always increasing (2n+3)</caption>
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*
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* ```js
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* const gen = nthCheck.generate([2, 3])
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*
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* gen() // `1`
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* gen() // `3`
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* gen() // `5`
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* gen() // `8`
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* gen() // `11`
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* ```
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*
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* @example <caption>With end value (-2n+10)</caption>
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*
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* ```js
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*
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* const gen = nthCheck.generate([-2, 5]);
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*
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* gen() // 0
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* gen() // 2
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* gen() // 4
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* gen() // null
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* ```
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*/
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export function generate(parsed) {
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const a = parsed[0];
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// Subtract 1 from `b`, to convert from one- to zero-indexed.
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let b = parsed[1] - 1;
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let n = 0;
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// Make sure to always return an increasing sequence
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if (a < 0) {
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const aPos = -a;
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// Get `b mod a`
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const minValue = ((b % aPos) + aPos) % aPos;
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return () => {
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const val = minValue + aPos * n++;
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return val > b ? null : val;
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};
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}
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if (a === 0)
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return b < 0
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? // There are no result — always return `null`
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() => null
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: // Return `b` exactly once
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() => (n++ === 0 ? b : null);
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if (b < 0) {
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b += a * Math.ceil(-b / a);
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}
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return () => a * n++ + b;
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}
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//# sourceMappingURL=compile.js.map
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